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Evaluate the definite integral
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lets see this warlock!
\[\int\limits_{2}^{8} (4/\sqrt(x)) dx \]
\[\int\limits_{2}^{8}\frac{4}{\sqrt{x}}dx=\int\limits_{2}^{8}\frac{4}{x^\frac{1}{2}}dx=\int\limits_{2}^{8}4x^\frac{-1}{2}dx=\frac{4*x^{\frac{-1}{2}+1}}{\frac{-1}{2}+1} ,x=2..8\]
\[\frac{4*x^\frac{1}{2}}{\frac{1}{2}}, x=2..8=2*4x^\frac{1}{2},x=2..8=8x^\frac{1}{2}. x=2..8\]
when I check my answer it gives me 11.3137.
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\[=8\sqrt{8}-8\sqrt{2}=8(\sqrt{8}-\sqrt{2})=8(2\sqrt{2}-\sqrt{2})=8(1\sqrt{2})=8\sqrt{2}\]
yes thats right good job
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