Find the bodies position at time t.

Question

anonymous · Answer

v=sin(pi/t), s(-6)=0

anonymous · Answer

v is the velocity.

a_clan · Answer

$$x=\int\limits_{?}^{?}v dt$$

anonymous · Answer

Given the velocity v=ds/dt and initial position of a body moving along a coordinate line, find the body's position at time t.   v = sin(pi(t))   s(-6)=0.

anonymous · Answer

That is pretty much the question and I'm confused at what it is asking as well.

a_clan · Answer

You have knowledge of basic calculus. right?

anonymous · Answer

Well I know your asking for [a,b] on the integrand. And vdt is velocity with derivate with respect to time.

a_clan · Answer

no, i am not asking for [a,b]. Those question marks are nothing, ignore them. We are dealing with indefinite integral here.
v=ds/dt
ds = vdt
Taking integral both sides,
$$\int\limits_{?}^{?}ds = \int\limits_{?}^{?}v dt + C$$
(Again, ignore question marks)
$$s=\int\limits_{?}^{?}\sin \pi(t)  + C$$
Once you have this equation in 't' variable with a constant 'C' , you put -6 in 't' and '0' in s to get the value of 'C'.
Substitute the 'value' of C in place of 'C' in the equation , to get final relation between s and t.