Use a change of variables to find the following indefinite integrals. \[ \int\frac{1}{\sqrt{1-9x^{2}}}\; dx \]
try 3x = sin(u) so 3dx = cos(u)du so we get int(du/3) = u/3 + C = arcsin(3x)/3 + C
That is impressive, how did you came up with u?
if you don't really need to understand the method here, you can find this form of equation and its solution in an integral table.
it's impressive to you...but i have done problems like this many times from experience. i came up with u because i knew that you can always integrate something of the form 1/sqrt(1 - u^2)...it's just arcsin(u) so i transformed the integral into something like that with a substitution
@jamesm, ah, that makes sense, it's kinda frustrating that they put this kind of exercise at the beginning of integral learning :(. Thanks for your help, I really appreciate it.
Join our real-time social learning platform and learn together with your friends!