If I make a triangle with two 90 degrees angles in a spherical body, is it still a triangle?
triangles aren't spheres
I know they aren't spheres, but what if i draw one on a sphere. I'm sorry if i didnt explain myself well, english isnt my first language
Than it would be a triangle on top of a sphere.
I'm going to go with not a triangle. a triangle is a 2 dimensional shape that is defined as having three non-zero angles that add up to 180 degrees. you can't make it have three dimensions.
a triangle can't have two 90 degrees angles...
traingles dont have two right angles
If you draw it on a sphere, the sides would not be straight line segments but curved lines...
Then if we draw a straight line on the floor, wouldn't it be curved too because the curvature of the earth?
hahahahaha... that was amazing...
In spherical geometry, you can have a spherical triangle with two right angles. This is impossible in euclidean geometry, but easily done in spherical geometry.
oh spherical traingle
Pictures are worth a thousand words.... (just took a class on spherical/hyperbolic/"Taxi Cab" geometry so this is fresh on my mind)
btw, ive gone through so much paper posting picture on this site <.< im destroying rain forests >.< its like im the bad guy from the movie Fern Gully >.>
me too lol i tried to save paper and right on the back too
it's not a triangle.... because a triangle must has 3 angles.. the sum of 3 angles is 180.. so 90+90=180 (it just 2 angles)... it cant a triangle... a triangle only have 1 right angle...
in spherical geometry the sum of the angles can be bigger than 180. You cant treat spherical like euclidean. All the formulas are different, units are different, etc.
a triangle is a polygon and polygons do not have curved sideand no triangle can have more than one right angle
The poster is talking about a triangle on a sphere, so we are talking about spherical triangles here, not "normal" (Euclidean) triangles. Yes, it is true that "normal" triangles cant have more than 2 right angles. Spherical triangles can. Look at the picture in the wiki article, read the caption under it. Look at the picture I drew. Its all there.
thank u joemath, that clears my doubt :D
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