Question

lim (x^2-4)/(x^3+8) x->-2

Answer 1

i wrote dnehere too????

Answer 2

{(x-2)(x+2)}/{(x+2)(x^2-2x+4)}
x+2 cancel
so
we have
(x-2)/(x^2-2x+4)
-4/(4+4+4)
-4/12
-1/3

Answer 3

marked wrong!!

Answer 4

azkhan the last problem had 90 in it right?
i didnt understand your response

Answer 5

isn that the same thing we had todo with the other questin????

Answer 6

noooo it had 9

Answer 7

sorry typo!!!

Answer 8

oh you wrote 90

Answer 9

that makes a difference the limit does exist then

Answer 10

(t^2-9)/(t-3)={(t-3)(t+3)}/{t-3}=t+3
as t->3, f(t)->3+3=6
limit is 6

Answer 11

(a^3+b^3)=(a-b) ...........??????

Answer 12

(a^2-2a+b^2)??????

Answer 13

Sum of Cubes:
(a³ + b³) = (a + b)(a² - ab + b²).

Answer 14

thank u!!!!

Answer 15

use l'hospital
expression bcomes
2x/3x^2
=2/3x
applying the limit,
2/3*-2=-1/3