Question

z belongs to C ,prove that product of z&conjugate of z=(modulus of z)sq.

Answer 1

\[z inC then prove, z*cojugate of z=\left| z \right|sq.\]

Answer 2

\[|z|=|a+bi|=\sqrt{a^2+b^2}\]
\[

Answer 3

\[z=a+bi,\bar z=a-bi\]
\[z\bar z =(a+bi)(a-bi)=a^2+b^2=|z|^2\]

Answer 4

since
\[(a+bi)(a-bi)=a^2+abi-abi-b^2i^2=a^2+b^2\]

Answer 5

steps clear?

Answer 6

yes thank you...

Answer 7

but also what does C means.?

Answer 8

C means "complex numbers"