Ellen wishes to mix candy worth $1.10 per pound with candy worth $2.57 per pound to form 28 pounds of a mixture worth $2.04 per pound. How many pounds of the more expensive candy should she use?

Question

anonymous · Answer

let x (pounds)=amount of candy worth $1.10
y=amount of candy worth $2.57
then you can build system of equations:
x+y=28
1.1*x+2.57*y=2.04*(x+y)
please solve it we'll compare answers

amistre64 · Answer

b at $ = t(z-x)
             ----- ; where t is total pounds; z=final price; x=other price
              ($-x)      and $ = price of amount in question... maybe

amistre64 · Answer

b@2.57 = 28(2.04 - 1.10)
                -------------- =abt 18lbs ...
                   (2.57 - 1.10)

amistre64 · Answer

17.905 is more accurate

anonymous · Answer

got the same answer from the system above.
i guess, it's the matter of convenience- there are few ways to solve the problem,.... as long as you understand what are you doing...
the answer should be the same.

amistre64 · Answer

i never understand what im doing ;)

amistre64 · Answer

a+x = t; a = t-b

ax+by=tz

(t-b)x +by = tz

tx - bx +by = tz

b(y-x) = t(z-x)

b = t(z-x)/(y-x) ...

anonymous · Answer

may be sometime... :)) like when you having lunch?

amistre64 · Answer

a+b = t that is lol