Question

26,249 is invested, part at 14% and the rest at 12%. If the interest earned from the amount invested at 14% exceeds the interest earned from the amount invested at 12% by 652.10, how much is invested at each rate?

Answer 1

You need to set up an equation for the interest earned from both parts of the investment.
Call the first amount, lets say "x". Now you need to define the second amount in terms of x. Now you might be thinking "I'll call it y" and that makes sense initailly but it also gives you two variables to deal with. Is there a way to define the second amount using the "x" again? Of course! It's the total minus the first amount, that is 26,249 - x.

Answer 2

Now, the interest earned on the first amount is what?
And the interest earned on the second amount is what?
The question states that the interest earned on the larger amount invested at 14% is $652.10 more than the amount of interest earned on the lesser amount invested at 12%. So set up an equation that relates these interest amounts to each other using the variable "x" that you defined before. When you find your x it's a cinch to find the other amount.