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Mathematics 20 Online
OpenStudy (anonymous):

How do i graph y= 6 + x/3? The original equation is 3y-x=6

OpenStudy (anonymous):

for starters u made a mistake when rearranging :|

OpenStudy (anonymous):

great help me!

OpenStudy (anonymous):

you didnt divide the 6 vy 3 :|

OpenStudy (anonymous):

Your line will cross the y-axis when x = 0 (at what is called the y-intercept). You can find where that is by replacing x in your equation with 0. i.e. y = 2 + 0/3 (zero div three is just zero, so the line crosses at y = 2) You can find other co-ordinate points by using different values for x and evaluating y. Since you need to divide your x value by 3, it would be a good idea to use values for x that are divisible by three.

OpenStudy (anonymous):

Wow thank you, I get what youre saying. I just didn't know exactly where to start.

OpenStudy (anonymous):

mathdrills, could u help me next?

OpenStudy (anonymous):

You could make a t table: x y 0 2 3 ? 6 ? 9 ? I left the ?, so you could fill in the blanks. Plot those points, use a ruler to construct a line, and you will have graphed the equation.

OpenStudy (anonymous):

Thank you very much!

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