Question

Find the vertex, the line of symmetry the maximum or minimum value of the quadratic function, and graph the function

f(x)3x^2-12x+12

Answer 1

3(x-2)(x-2)

Answer 2

use x = -b/2a

Answer 3

a = 3, b = -12

Answer 4

equation for vertex(maximum/minimum).
If u have a quadratic in the form of y=ax^2+bx+c
then the vertex is when x=-b/2a

Answer 5

(2,0)

Answer 6

This would be your minimum value

Answer 7

x = 2 is line of symmetry

Answer 8

in this case
a=3
b=-12
c=12
so using the equation:
x=-(-12)/(2*3)=2
so solve for the y value

Answer 9

I just needed the first part thanks