Question

Determine whether the improper integral converges or diverges.∫[0 on top &-∞on the bottom] e^x dx

Answer 1

cobverges

Answer 2

this
int e^x = 1

Answer 3

\[\int\limits_{-\infty}^{0}e^x dx=\lim_{b \rightarrow -\infty}\int\limits_{b}^{0}e^x dx=\lim_{b \rightarrow -\infty} e^x, x=b..0\]
\[\lim_{b \rightarrow -\infty}(e^0-e^b)=1-\lim_{b \rightarrow -\infty}e^b=1-0=1\]

Answer 4

gj nikita

Answer 5

i hope you know what i mean when i e^x, x=b..0
that means i'm just fixing to evaluate e^0-e^b okay?

Answer 6

ok.understood!

Answer 7

i did that last time on a previous problem with you tonight

Answer 8

yes. thanks. which country r u from?

Answer 9

i can't use the other symbol or if i can i don't know how
so i made up my own notation for it

Answer 10

usa

Answer 11

ok. i'm from Singapore.

Answer 12

i heard of your country but know little about it lol
i'm just a dumb american

Answer 13

haha

Answer 14

Oh guys! I'm from Russia)

Answer 15

oh i see

Answer 16

nikita is that your real pic?

Answer 17

pic=picture

Answer 18

you knew that lol

Answer 19

hm? yes)

Answer 20

you look cute

Answer 21

and so do you joe lol

Answer 22

lol thanks :)

Answer 23

i need to buy a calculus book or something, im very very very very weak in calculus :(