Question

limθ tends to 0[sinθ-θ]/[θ-tanθ]

Answer 1

it Is -1

Answer 2

\[\frac{\sin (\theta)-\theta}{\theta-\tan(\theta)}*\frac{\frac{1}{\theta}}{\frac{1}{\theta}}=\frac{\frac{\sin(\theta)}{\theta}-1}{1-\frac{\tan(\theta)}{\theta}}\]

\[=\frac{\frac{\sin(\theta)}{\theta}-1}{1-\frac{\sin(\theta)}{\cos(\theta)*\theta}}\]

so we 0/0 we should had used l'hospital way

Answer 3

\[\frac{\cos (\theta)}{-\sec^2(\theta)}=-\cos^3(\theta)\]

Answer 4

now plug in 0
in you will get -1

Answer 5

it is olready in 0/0 form ...

jus use lhopitals rule once nd substitute Theta =0

Answer 6

i know i seen that after i got that far lol

Answer 7

ya happens some time :P LoL

Answer 8

yep yep

Answer 9

ok.