Question

wat is integral of 2 power logx?

Answer 1

Let u=log x

Answer 2

2^logx

Answer 3

logx = e^( log (log(x) )

Answer 4

\[\int\limits_{}^{}2^{logx}dx\]

Answer 5

ya dats true myininaya

Answer 6

i was just writing it the way i like to see it lol

Answer 7

e^(log(2) ) =2

Answer 8

so 2^log(x) = [ e^(log(2) ) ]^ log(x)

Answer 9

= e^[(log2)(logx)]

Answer 10

not sure if its getting anywhere

but its similiar to integrating or differentiating something like 2^x

Answer 11

You've got the solution right there elec.
2^log(x) = [ e^(log(2) ) ]^ log(x) = [ e^(log(x) ) ]^ log(2) = x^log(2) = x ^(log(2) + 1)/(log(2) + 1)

Answer 12

or x*x^log(2) / [1 + log(2)]

Answer 13

2^logx = x^log2 solve it !!

Answer 14

\[2^{logx} = x ^{\log2} \]

substitute this n ull find the integral of the form \[x ^{?}\]

Answer 15

blacksteel can u just give me the correct explanation for this??i meant step by step?

Answer 16

Use this old trick that is usually used for the derivative and apply it to the integral. Let\[y =2^{\log x}\]\[\ln y =(\log x)(\ln 2) \]Take integral both sides. It becomes integral of log x with the coefficient ln 2.