Question

find the sum of the finite geometric series by using the formula for sn

1-1/2+1/4-1/8+1/16-1/32+1/64-1/128

the sum of the finite geometric series is???

Answer 1

a=1/2

r=-1/2

S=a/ (1-r)

Answer 2

\[Sn = (a(1-r^n)) / (1-r)\]

Answer 3

=(1/2) / (3/2) = (1/2) (2/3) = (1/3)

Answer 4

oh i thought it said infinite, but yeh same thing, it will be extremely close to 1/3

Answer 5

thank u...