2y+x=4
3y-2x=13
x=-2,y=3
Just trying to plot these lines on a linear graph.
I come up with the right x and y values for the second equasion- y=2x/3+13/3 but when I when I make a table of values for the first equation, I keep coming up with x=-2,y=1 based on y=x/2+2.
Can anyone help?

Question

anonymous · Answer

y=-1/2 x +2
y=2/3x +13/3

anonymous · Answer

So plot these two lines

anonymous · Answer

cheers... i had that on the first attempt but must of done something stupid.....again!
hang on, i didn't have the negative gradient.
I knew the gradient was a 1/2 and the y intercept was 2...

anonymous · Answer

Yeah, when you moved the x to other side, it should have been -x

id21 · Answer

attachment

anonymous · Answer

2y+x=4  multiply this by 2 we get  4y+2x=8
3y-2x=13                                       3y-2x=13     add these two together                                      -----------
                                                        7y      =  21
                                                           y=3 ans........................subst this to eq 1
  we get       2(3)+x=4
                            x= 4-6=-2  ans.. 
 so the ans is (-2,3)=(x,y)

anonymous · Answer

id21....that wolfram program looks amazing!

id21 · Answer

You can use it by yourself! :) It is online http://www.wolframalpha.com

anonymous · Answer

To plot a bunch of function:  
example 2x and x^2 from 0 to 2
Plot[{2x,x^2},{x,0,2}]

id21 · Answer

I used this syntax:  plot y=2x/3+13/3 and y=-x/2+2 from -4 to 4