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what is the domain of p? p(x)2- 2x+3
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x is 2 to the square just don't know how to write it
p=x^2-2x+3?
p(x)=x^2-2x+3. is that it??
In that case the domain is the entire real axis. You can plug any value in for x as there are no roots or divisions.
thank u for showing me where that sign was Thomas. u are a life saver
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If the above equation is written correctly, then @Thomas9 is right. You start off with \[(-\infty,\infty)\]and then from there you look for any square roots or division by a variable to start eliminating points from the domain, but in this case you have neither. So we are just left with what we started with, \[(-\infty,\infty)\]
thank u
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