Question

lim x tends to θ[sinθ-θ]/[θ-tanθ]

Answer 1

jah, can u solve?

Answer 2

\[\lim_{x \rightarrow \theta}(\sin (\theta)-\theta)/(\theta \tan (\theta))\]?

Answer 3

jah, can u solve?

Answer 4

denominator theta -(minus) tan theta

Answer 5

jah, can u solve?

Answer 6

and sorry theta tends to 0

Answer 7

jah, can u solve?

Answer 8

ok?

Answer 9

ok that makes more sense. ill try

Answer 10

math - did u get an answer to the integration problem

Answer 11

i've solved it now

Answer 12

jah, can u solve?

Answer 13

can tell me ur ans plz

Answer 14

i got 1/2.

Answer 15

jah wat r the steps?

Answer 16

jimmy wat was the ans to e previous qn?

Answer 17

have u learned l'hopital's rule are u supposed to figure it out without it?

Answer 18

oh - its ok i misinterpreted the question - i integrated
x / (x^2 -1 )^2 - i've just looked at the previous post.

Answer 19

i ve learned l'hopital's rule. then how?

Answer 20

steps..

Answer 21

then by using l'hopitals rule u take the derivative of the numerator seperately from the denominator so:
\[(\sin(\theta)-\theta)/(\theta-\tan(\theta))\] becomes
\[(\cos(\theta)-1)/(1-\sec^2(\theta))\] then u have to do it again so it becomes
\[(-\sin(\theta))/(-2\sec(\theta)\tan(\theta))=(\sin(\theta))/(2\sec(\theta)\tan(\theta)\]
and then 1 more time so its solvable:
\[(\cos(\theta))/(2(\sec(\theta)\tan^2(\theta)+\sec^3(\theta)))\]
now u can input the 0 for theta and solve

Answer 22

sec^3 theta sub 0 is 1 right?

Answer 23

yes

Answer 24

cos(0)=1
sec(0)=1
tan(0)=0

Answer 25

that means tan0=1

Answer 26

how to get 1/2 as ans

Answer 27

tan(x)=sin(x)/cos(x)
sin(0)=0
cos(0)=1
tan(0)=0/1=0

Answer 28

pls leave ur steps, i'm signing out.

Answer 29

\[(\cos(0))/(2(\sec(0)\tan^2(0)+\sec^3(0))\]
cos(0)=1
sec(0)=1 sec^3(0)=1^3=1
tan(0)=0 tan^2(0)=0^2=0
so its:
(1)/(2(1*0+1))=
1/(2(0+1))=
1/(2(1))=
1/2