there is a picture attached. please show all the work
we discovered earlier with this that the ratios are: 4/25 that leaves the rest of it to be: 1-4/25 = 21/25 the probability that it lands in the bottom is then: 21/25
i dont get it?
the area of the shade is: radius of 4; 4^2 pi = 16pi all togheter; 16pi(3)/4 = 12pi for part of the cirlce the trianlge tha tis left shaded is a 45 degree and is just 4*4/2 = 8 8+12pi should be the total shaded area
ohh
got that one
ihave # 23, 24, 25, and 27 left
the radius of the circle .. hmm 6 = sqrt(3)*6/sqrt(3); so the radius = 6/sqrt(3); or prettier to look at..... 6sqrt(3)/3 = 2sqrt(3) the area of the circle then is (2sqrt(3))^2 pi = 12pi the area of the triangle in total is: 12^2 sqrt(3)/4, or simply 36sqrt(3) total area of tri - area of circle is: 36sqrt(3) - 12pi
ihave # 23, 24, 25, and 27 left
is this #27?
#23 is: 6 sin(t) b/5 ---------- 15sin(t) b/2 6/5 2/5 ---- = ----- = 4/25 15/2 5/2 #24 is: NOT the ratio of the triangle :) 1 - 4/25 = 21/25 as its ratio
ihave # 23, 24, 25, and 27 left
whats sin(t) stand for....
the probability that something will fall into the bottom quad there is 21/25
sin(t) stands for the height of the triangles .... since we dont know what "t" is we just make it generic and it goes away in the process
oh
so whats the answer for 23?
amistre64?
i only need help for 23, 24, and 25 now!!
I had given solution for this earlier based on similar triangles... seems u hv deleted that n posed the question again...
oh i didnt realize that
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