please help with this..i need to make it into a fraction for the answer but honestly i hate fraction please help...http://www.webassign.net/cgi-bin/symimage.cgi?expr=int_%28-2%29%5E%281%29%20%5C%28x%5E3-4%20x%5C%29%20dx

Question

anonymous · Answer

i got $${(x^4/4) - (4x^2/3)}\left(\begin{matrix}1 \ -2\end{matrix}\right)$$

anonymous · Answer

isnt it 4x^2/2 or 2x^2

anonymous · Answer

no you have to do the formula of n+1/n+1 too...i think

anonymous · Answer

i'm talking about the integral of 4x - mathrick has got it

anonymous · Answer

ugh..its soo hard!!!!

anonymous · Answer

$$(x^4)/4-2x^2$$$$\left\{ (-2)^4/4-2(-2)^2 \right\}-\left\{ 1^4/4-2(1^2) \right\}$$

anonymous · Answer

thanx Jimmy

anonymous · Answer

but its 4x^2 and the deminator would n+1 so thats 3

anonymous · Answer

ok but then can you help me with the desimal into fracction please...

anonymous · Answer

Not to make fun, but it is the simplest integral, straight forward.

anonymous · Answer

what about decimal to fraction?

anonymous · Answer

do u have a question just post it

anonymous · Answer

oops. Mathfrick has the -2 and the 1 reversed in his post. The answer is 9/4.

anonymous · Answer

It should be 1^4 - 2 -[(-2)^4/4 - 2(-2)^2] =
-7/4 - (4 - 8) = -7/4 + 4 = 9/4

anonymous · Answer

ok thanks : )

anonymous · Answer

thats correct - i missed that - well done FF