Rearrange x=2/3 y squared +4
ready to work on this together?
that would be great
Sweeet! Ok, first thing we want to do is to try to get the y on one side and the rest of the junk on the other side of the equals sign.
Easiest thing to remove is the +5. How do we get rid of it from the right side of the equals sign?
-4
2/3y^2=x-4 multiply by 3/2 next?
Oooohhhh I'm sorry. I mixed you up with someone else. -4 IS correct. Sorry!
You're absolutely correct. multipy by 3/2 (which is technically the same as dividing by 2/3)
y^2=3/2x-4 *then remove the root?
power of two i mean
Yes, to do this, you square root everything on both sides.
y=sqrt of 3/2x-4 ????
wolfram alpha gives me a different solution to that
Weird. Lemme write this out in pencil then.
I got the same answer. :/ Scroll down to where it says "answers for y"
they give me this....is that the exact same sort of answer as what i got?
Yup! They just put a separate square root on each expression. It's still the same answer.
their answer actually appears to look like sqrt3/2 multiplied by sqrtx-4
Basically, they didn't distribute the square root in wolfram alpha.
Yup! Same thing :D
For example: Square root of 4 times square root of four. How much is that?
4
I had the right answer the first time I did it. I guess I just needed to confirm it!
and if you combined the suare root and said "square root of (4 times 4)"?
No problemo.
I sorta assumed that, just good to hear someone else confirm it ie "sqrt(4 x 4)
hey uber, I asked this question last night and "mathlearner" gave me a different answer....I think his is wrong. http://openstudy.com/groups/mathematics#/groups/mathematics/updates/4e180a500b8bc2275746b45b
Hmmm.... it might be correct, but that is very weird notation. Lemme double check.
According to wolfram, it's false. http://www.wolframalpha.com/input/?i=x%3D+2%2F3+y%5E2+%2B+4+%3D+sqrt%282-4x%2F3x%29
I think he has too many X's. They should cancel out the way he wrote it.
2x/3x should just equal 2/3 with no x
you're right.he does have one too many Xs.
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