A flag is raised while an onlooker watches from a distance of 11 feet away from the base of the flag pole (see the figure below). The flag rises vertically at a rate of 5 inches per second. Let t denote the time (in seconds) after the flag begins to rise (For simplicity, assume that when the flag begins to rise it is 0 inches above the ground). Express the distance d (in feet) between the flag and the onlooker as a function of t. d(t)=
you know you are tired when you hit scan without putting the picture in the scanner >.>
haha i have like 3 questions left! almost there!
i just did that i been scanning nothing lol
okay pretend i drew my triangle in quadrant one
just for clarification, yes, that guy is looking at the flag with his feet.
i cant get my thingy to post :(
hahha ok let me try. one sec.
what? :( try logging out and logging back in?
ok it didnt work so just to clarify: sqrt121+25t/144 ?
5in=5/12 ft
\[\sqrt{121+\frac{25t}{144}}\]
WHOOPS, forgot the squre on the t lol, my bad >.<
so 25t^2
\[\sqrt{121+\frac{25t^{2}}{144}}\]
yes :)
YAY! i got another one and then im almost done. check it out for me?
lol sure
k, just posted it.
im hungry >.<
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