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Mathematics 18 Online
OpenStudy (anonymous):

A flag is raised while an onlooker watches from a distance of 11 feet away from the base of the flag pole (see the figure below). The flag rises vertically at a rate of 5 inches per second. Let t denote the time (in seconds) after the flag begins to rise (For simplicity, assume that when the flag begins to rise it is 0 inches above the ground). Express the distance d (in feet) between the flag and the onlooker as a function of t. d(t)=

OpenStudy (anonymous):

OpenStudy (anonymous):

you know you are tired when you hit scan without putting the picture in the scanner >.>

OpenStudy (anonymous):

haha i have like 3 questions left! almost there!

myininaya (myininaya):

i just did that i been scanning nothing lol

myininaya (myininaya):

okay pretend i drew my triangle in quadrant one

OpenStudy (anonymous):

just for clarification, yes, that guy is looking at the flag with his feet.

myininaya (myininaya):

i cant get my thingy to post :(

OpenStudy (anonymous):

hahha ok let me try. one sec.

OpenStudy (anonymous):

what? :( try logging out and logging back in?

OpenStudy (anonymous):

ok it didnt work so just to clarify: sqrt121+25t/144 ?

myininaya (myininaya):

5in=5/12 ft

OpenStudy (anonymous):

\[\sqrt{121+\frac{25t}{144}}\]

OpenStudy (anonymous):

WHOOPS, forgot the squre on the t lol, my bad >.<

OpenStudy (anonymous):

so 25t^2

OpenStudy (anonymous):

\[\sqrt{121+\frac{25t^{2}}{144}}\]

OpenStudy (anonymous):

yes :)

OpenStudy (anonymous):

YAY! i got another one and then im almost done. check it out for me?

OpenStudy (anonymous):

lol sure

OpenStudy (anonymous):

k, just posted it.

OpenStudy (anonymous):

im hungry >.<

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