Question

x^2+3x-7=0

Answer 1

I need my answer checked please

Answer 2

well I want to see if you come up with the same answer I should say.

Answer 3

\[\left\{\left\{x=\frac{1}{2} \left(-3-\sqrt{37}\right)\right\},\left\{x=\frac{1}{2} \left(-3+\sqrt{37}\right)\right\}\right\} \]

Answer 4

-3+√37 -3-√37
-------- , --------
2 2

Then I need the approximate solution to 3 decimal place x=


I got 1.541, -4.541

Answer 5

That is what I got is that wrong!!!!

Answer 6

-3+√37 -3-√37
-------- , --------
2 2

Then I need the approximate solution to 3 decimal place x=


I got 1.541, -4.541

Answer 7

\[\frac{1}{2} \left(-3-\sqrt{37}\right)=-4.54138 ,\frac{1}{2} \left(-3+\sqrt{37}\right)=1.54138 \]

Answer 8

Ok so what you have here then that is what I need to put down cause what I have worked out is wrong. how did you get the 1/2 before.

Answer 9

Even if it say "use radical as needed"?

Answer 10

I am doing radical expression and quadratic equation.

Answer 11

its the same thing,
5/2 = 1/2 * 5

If it says use radicals as needed
then use
-3+√37 -3-√37
-------- , --------
2 2

Answer 12

ok and what about the 3 decimal?

Answer 13

\[\frac{1}{2} \left(-3+\sqrt{37}\right)=\frac{1}{2} *\frac{-3+\sqrt{37}}{1}=\frac{-3+\sqrt{37}}{2} \]Your answers look fine to me. The fractions are OK in form.

Answer 14

ok i wanted to make sure that I am doing it correctly thanks guys and gales. I will be on more for help and checking answers.