Question

Solve for x

x^2+50=10x

Answer 1

I got x=5+5i, 5-5i

I need the answer in the form a+bi, how do I do that?

Answer 2

x^2+50-10x=10x-10x
x^2-10x+50=0
using
ax^2+bx+c=0
where
a=1, b=-10 c=50
\[x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}=\frac{-(-10) \pm \sqrt{(-10)^2-4(1)(50)}}{2(1)}\]

Answer 3

so that is the answer then myininaya

Answer 4

\[x=\frac{10 \pm \sqrt{100-200}}{2}=\frac{10 \pm \sqrt{-100}}{2}=\frac{10 \pm i10}{2}\]
yes you are right

Answer 5

which one then the top or bottom

Answer 6

what do you mean?

Answer 7

the top answer or the bottom won before u say ur right

Answer 8

its all the same

Answer 9

ok

Answer 10

but i said you were right
(10+10i)/2 is 5+5i
and
10-10i)/2 is 5-5i