Question

Solve the equation log10x = 1/4log10*16 +1/2log10*49

the log is base 10.

Answer 1

\[\log(10x)=\log(10*2^4)^{\frac{1}{4}}+\log(10*7^2)^{\frac{1}{2}}\]

Answer 2

\[\log(10x)=\log(10*2)+(\log10*7)\]

Answer 3

\[\log(10x)=\log(20*70)\]

Answer 4

I dont understand. I thought 10 was the base. Are we supposed to multiply the base?

Answer 5

log10x is base

1/4log10*16
all 10 is base?

Answer 6

Yes.

Answer 7

\[\log _{10}(n)+\log _{10}(m)=(n*m)\]

Answer 8

Oh I see. I understand now. Thank you.

Answer 9

\[\log(10x)=\log(1400)\]

Answer 10

10x=1400
\[x=\frac{1400}{10}=140\]
x=140

Answer 11

Thank you.

Answer 12

ty

Answer 13

I was wrong first line:\[\log(10x)=\log(10*(2^4)^\frac{1}{4}) + \log (10*(7^2)^{\frac{1}{2}})\]

Answer 14

So what is the answer now?

Answer 15

The same answer, I just rewite the first line that all