Question

an object is dropped from rest.if it falls a distance during S1 during the 1st second and an additional distance S2 in the next second.the ratio of S1/S2 is
a-1
b-3
c-2
4-5

Answer 1

i think it should be b........... in first second its velocity increases frm 0 to g......
then applyin eq of motion s= 0.t - gt^2
---
2
which becomes g
---
2


then in second second (it funny writing scond second) its velocity incrs frm g to 2g


again applying eq of motion


now rembr int velocity is g for the second second.......the final for the first second
s = gt + gt^2
-----
2
as time diff is 1

s = g + g
----
2



s= 3g
--------
2


compare dist traveld and u get ur ratio :)

Answer 2

\[ r(t) = h_0 + v_0 + {g t^2 \over 2}\]for this example, h_0 and v_0 are both 0.
\[{s_1 \over s_2} = {{r(1)} \over {r(2)-r(1)}} = {{{g} \over {2}} \over {{4g \over 2}-{g \over 2}}} = {1 \over 3}\]Therefore, none of the above is correct. Most likely it's a typo and you swapped numerator and denominator when copying the problem...