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Mathematics 9 Online
OpenStudy (anonymous):

How do i find vertical asymptotes ?

OpenStudy (somethingawesome):

Vertical asymptotes occur when the function divides by zero and the limit is infinity. For example, \[f(x) = \frac{x+1}{x-1}\] has a vertical asymptote at x=1. Be careful to distinguish between VAs and removable discontinuities: \[f(x) = \frac{x+1}{x^2-1}\] Setting the denominator equal to zero gets x^2-1 = 0 with solutions x = 1 and x = -1, but \[ \lim_{x\rightarrow -1} \frac{x+1}{(x+1)(x-1)} = \lim_{x \rightarrow -1} \frac{1}{x-1} = -1/2\] so one of those "divide by 0"s is just a hole, not a vertical asymptote. We can't cancel away the x-1 in the denominator, so as x goes to 1 the function blows up to infinity, giving us a VA.

OpenStudy (anonymous):

Thanks

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