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Mathematics 19 Online
OpenStudy (anonymous):

Hi how can i find the domain of [(2x^3)-5]/(x^2+x-6)

myininaya (myininaya):

go joe!

myininaya (myininaya):

i'm sleepy i couldn't go to sleep last night :(

OpenStudy (anonymous):

you dont want the denominator of the fraction to be 0. so lets factor that quadratic and see what x cant be.

OpenStudy (anonymous):

=/ i got a little sleep, but not a lot, i dont know what im doing up yet lol

OpenStudy (anonymous):

and those numbers that cant work are the domain?

OpenStudy (anonymous):

yes, that is correct mlo, the numbers we get from setting the denominator = 0 are the numbers that cant be in the domain, everything else is ok

OpenStudy (anonymous):

alright THanks!!!! (:

OpenStudy (anonymous):

so we have: \[x^{2}+x-6 = 0 \Rightarrow (x+3)(x-2) = 0 \Rightarrow x = -3, x = 2\] so our domain is all real numbers, except for -3 and 2

OpenStudy (anonymous):

that's what i got, Thank you (:

myininaya (myininaya):

gj you

OpenStudy (anonymous):

a person that can actually do some of the work themselves...youre awesome mlo! @myininaya thank you :)

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