Hi how can i find the domain of [(2x^3)-5]/(x^2+x-6)
go joe!
i'm sleepy i couldn't go to sleep last night :(
you dont want the denominator of the fraction to be 0. so lets factor that quadratic and see what x cant be.
=/ i got a little sleep, but not a lot, i dont know what im doing up yet lol
and those numbers that cant work are the domain?
yes, that is correct mlo, the numbers we get from setting the denominator = 0 are the numbers that cant be in the domain, everything else is ok
alright THanks!!!! (:
so we have: \[x^{2}+x-6 = 0 \Rightarrow (x+3)(x-2) = 0 \Rightarrow x = -3, x = 2\] so our domain is all real numbers, except for -3 and 2
that's what i got, Thank you (:
gj you
a person that can actually do some of the work themselves...youre awesome mlo! @myininaya thank you :)
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