Question

logbase 2(x+3) + log base 2(x-3)=4

how do i solve for x

Answer 1

go myininaya :)

Answer 2

\[\log_2((x+3)(x-3)=4\]
2^ 2^
\[(x+3)(x-3)=2^4\]
\[x^2-9-2^4=0\]
\[x^2-9-16=0\]
\[x^2-25=0\]
x=5,x=-5
but omg no we cant have x=-5 do you know why?

Answer 3

because the inside of a log can't be negative or 0
log(-5+3)
log(-5-3)
both of these insides are negative
even it just one was then we would not consider x=-5 as a solution

Answer 4

so only solution x=5