Solve this equation? e^(2^x) = (e^3x) (1/(e^2))
\[e^{2^x}=\frac{e^{3x}}{e^2}\]?
if so, right hand side is \[e^{3x-2}\] and since exp is a one to one function your job is to solve \[2^x=3x-2\]
unless the left hand hand side is \[(e^2)^x\]
in which case you solve \[2x=3x-2\]
in which case you get x = 2 by inspection
actually 2 is a solution to \[2^x=3x-2\] as well, but there is also another solution that i have no idea how to find using algebra
yes the first one is how it looks
hello sensei! did you see that my myininaya is a \[\color{red}{\text{master!}}\]
well if it is the first one 2 is a solution. there is another solution that i can find graphically. maybe there is some other way to find it. that is there are two solutions to \[2^x=3x-2\]
i saw :) they grow up so fast these days
lol
we are all following in your footsteps
i hope not lol
hey how about \[\color{green}{\text{children of amistre}}\] as the next level?
with any luck yall do better :)
amistre how did you become moderator? and do you have any cool chores?
like do they make you get the e-pizza?
its by invitations; not really an experience level. my chores are to pretty much try to encourage safe interneting .. and take out the trash
so you don't get the e-pizza? thats lame
they make me grovel and beg for a window seat :)
lol
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