Question

Determine the points at which the graph of the following function has horizontal tangent.
y = x^2/X^2-4

Answer 1

take the derivative, set = 0 and solve.

Answer 2

derivative is
\[\frac{-8x}{(x^2-4)^2}\] so set
\[-8x=0\] and get
\[x=0\]

Answer 3

\[f'(x)=\frac{2x(x^2-4)-x^2(2x)}{(x^2-4)^2}=\frac{2x(x^2-4-x^2)}{(x^2-4)^2}=\frac{2x(-4)}{(x^2-4)^2}\]

Answer 4

my myininaya will write the steps

Answer 5

oh right, before i can even finish

Answer 6

so point is
\[(0,0)\]