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Mathematics 11 Online
OpenStudy (anonymous):

if I am given two points on the diameter of a circle, how do I come up with a standard form equation for that circle? I was given (-2,4) and (4,2). I think the center of the circle is at (1,3) but I may be wrong.

OpenStudy (anonymous):

What formula did you use to find the center?

OpenStudy (anonymous):

find the midpoint (that's the center), then find the distance between the two and divide by two to get the radius

OpenStudy (anonymous):

Yep, I agree

OpenStudy (anonymous):

then plug that information into the equation of a circle formula

OpenStudy (anonymous):

I did not use a formula, I just drew it on a piece of graph paper and counted units from point to point. Halfway was a 1,3... yeah I know that is not right, but I have no clue what the heck I am doing here!

OpenStudy (anonymous):

\[(x-h)^{2}+(y-k)^{2}=r ^{2}\](h,k) is center, r is radius, half the distance between two given points.

OpenStudy (anonymous):

ok, I am confused here... how do I determine the center??

OpenStudy (anonymous):

There are several ways, one way is to find the midway point of the two given points. The midpoint formula\[((x _{1}+x _{2})/2, (y _{1}+y _{2})/2) \]

OpenStudy (anonymous):

ahhhhh.... that I can work with, thanks!

OpenStudy (anonymous):

sweet, my center point was right... but it was just dumb luck I am sure... LOL

OpenStudy (anonymous):

Sure you can count the graph, but it is not a very efficient method. For example, in a test it may not be given on a graph and may take too much time to make a graph.

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