Help! Find the exact value of the expression w/o a calculator? (1/(sec^2 40 degrees)) + (1/csc^2 40 degrees) Can you explain too?
easy
lolno
= cos^24 + si^2 40 = 1
use x instead of 40 might make it easier
good thing openstudy isnt a calculator :)
find 2 degrees that you already know to calculate with
I was going to say that
yes - this is a standard trig identity: cos^2x + sin^2x = 1
I was also going to say find csc(40) * csc (40)
\[\frac{1}{\sec^2(x)}+\frac{1}{\csc^2(x)}=\cos^2(x)+\sin^2(x)\]
finally someone saw it lol, nice job satellite :)
the "40" degrees is a red herring. makes no difference what the input is, you will get 1 in any case
Tricksters. ty!
yw from all of us i am sure
There's more than one way to go about this, but knowing the identity helps
my scanner isnt as fast as satellite lol :( i need a new scanner >.>
wow that was fast. mine takes like ten minutes
not fast enough! haha
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