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OpenStudy (anonymous):
Help! Find the exact value of the expression w/o a calculator?
(1/(sec^2 40 degrees)) + (1/csc^2 40 degrees)
Can you explain too?
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OpenStudy (anonymous):
easy
OpenStudy (anonymous):
lolno
OpenStudy (anonymous):
= cos^24 + si^2 40 = 1
OpenStudy (anonymous):
use x instead of 40 might make it easier
OpenStudy (amistre64):
good thing openstudy isnt a calculator :)
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OpenStudy (amistre64):
find 2 degrees that you already know to calculate with
OpenStudy (anonymous):
I was going to say that
OpenStudy (anonymous):
yes - this is a standard trig identity:
cos^2x + sin^2x = 1
OpenStudy (anonymous):
I was also going to say find csc(40) * csc (40)
OpenStudy (anonymous):
\[\frac{1}{\sec^2(x)}+\frac{1}{\csc^2(x)}=\cos^2(x)+\sin^2(x)\]
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OpenStudy (anonymous):
finally someone saw it lol, nice job satellite :)
OpenStudy (anonymous):
the "40" degrees is a red herring. makes no difference what the input is, you will get 1 in any case
OpenStudy (anonymous):
Tricksters. ty!
OpenStudy (anonymous):
yw from all of us i am sure
OpenStudy (anonymous):
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OpenStudy (anonymous):
There's more than one way to go about this, but knowing the identity helps
OpenStudy (anonymous):
my scanner isnt as fast as satellite lol :( i need a new scanner >.>
OpenStudy (anonymous):
wow that was fast. mine takes like ten minutes
OpenStudy (anonymous):
not fast enough! haha
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