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Mathematics 21 Online
OpenStudy (anonymous):

I am suppose to be finding the max volume ofr a rectangular solid with a square base. I am having trouble coming up with the volume formula for such a figure. can someone help?

OpenStudy (anonymous):

you must have some constraint yes? like the area of the sides or the dimensions of a piece of paper?

OpenStudy (amistre64):

area of base times height of solid

OpenStudy (anonymous):

got it

OpenStudy (anonymous):

if the area is fixed make a cube

OpenStudy (amistre64):

\[\int_{0}^{h} x^2dx\]

OpenStudy (anonymous):

is it 1 ---pi * a^2*h ? 3

OpenStudy (anonymous):

unless you don't need the top. then it changes. not sure what the exact problem is, but you stated you need a maximum so i am thinking that this is a calc problem with something fixed

OpenStudy (amistre64):

i think my fancy shmancy way is off :)

OpenStudy (anonymous):

yeah it is off. and there is no pi in this either.

OpenStudy (anonymous):

yea no pi .... :)

OpenStudy (anonymous):

pi makes everything better.

OpenStudy (amistre64):

dont need a pi to get area of a square ... just gotta sum up the areas up to the height

OpenStudy (anonymous):

usually area is fixed. so if area = A and you don't need a top then base is \[x^2\] height is \[h\] and volume is \[V=x^2h\] which given that \[A = x^2+4xh\] allows you to solve for h as \[h=\frac{A-x^2}{4x}\]and gives \[V(x)=x^2\times \frac{A-x^2}{4x}\] so something like that.

OpenStudy (anonymous):

then find the max by taking derivative etc etc

OpenStudy (anonymous):

sir joemath please answer my question

OpenStudy (anonymous):

what does x represtn in this ewuation?

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