Question

find the sum of the finite geometric series by using the formula for Sn

1-1/3+1/9-1/27+1/81-1/243+1/729

Answer 1

Do you mean infinite? otherwise you could just add them together.

Answer 2

infinite

Answer 3

finite geometric series

Answer 4

The equation to solve a geometric progression:
\[a(1-r^{n+1})/(1-r) = \sum_{n}^{0}ar^n\] Since a = 1, r = -1/3, and n = 6:
\[1(1-(-1/3)^7)/(4/3) = 0.750342936\]