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OpenStudy (zarkon):
\[\lim_{n\to\infty}\cos(2/n)=\cos(0)=1\]
OpenStudy (anonymous):
well, as n goes to infinity, or to zero?
OpenStudy (anonymous):
the sequence
\[\frac{2}{n}\]
converges to 0 as n gets larger and larger, so the sequence:
\[\cos(\frac{2}{n}) \rightarrow \cos(0) = 1\]
OpenStudy (anonymous):
thank you
OpenStudy (anonymous):
i can never remember what the restrictions are for converging or diverging
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OpenStudy (anonymous):
It diverges based off the nth term test for divergence. Which is what Zarkon wrote. The only way a series can converge is if the lim is zero.
\[\sum_{n=1}^{\infty}a_n\]
converges if and ONLY if
\[\lim_{n \rightarrow \infty}a_n=0\]
OpenStudy (anonymous):
i think hes talking about the sequence, not the series.
OpenStudy (zarkon):
that is not true
OpenStudy (anonymous):
For series, it is true. It is not true for sequences.
OpenStudy (anonymous):
Well, that is misleading I suppose. The limit can be zero and it can still diverge. But I mean, if it converges, the lim is zero.
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OpenStudy (zarkon):
\[\lim_{n\to\infty}a_n=0\] is a necessary condition not a sufficient condition