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A square matrix is said to be 'idempotent' if A^2 = A. Show that if A is idempotent then 2A-I is invertible and is its own inverse?
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(2A -I)^2 = 4A^2 - 4A + I = I
Oh man that was so simple don't why I didn't think of that
but wait how do you know if its its own inverse?
An identity matrix is its own inverse right? Just making sure
he multiplied it with itself and got I
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and yes the identity matrix is its own inverse
2A-I is invertible because it has inverse one.
Okay gotcha
sir joemath answer my question please
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