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Mathematics 19 Online
OpenStudy (anonymous):

A square matrix is said to be 'idempotent' if A^2 = A. Show that if A is idempotent then 2A-I is invertible and is its own inverse?

OpenStudy (nikita2):

(2A -I)^2 = 4A^2 - 4A + I = I

OpenStudy (anonymous):

Oh man that was so simple don't why I didn't think of that

OpenStudy (anonymous):

but wait how do you know if its its own inverse?

OpenStudy (anonymous):

An identity matrix is its own inverse right? Just making sure

OpenStudy (anonymous):

he multiplied it with itself and got I

OpenStudy (anonymous):

and yes the identity matrix is its own inverse

OpenStudy (nikita2):

2A-I is invertible because it has inverse one.

OpenStudy (anonymous):

Okay gotcha

OpenStudy (anonymous):

sir joemath answer my question please

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