5/8x+1/16x=5/16+x the solution is x=? help please??
is the x in the denominator?
5/8x+1/16x=5/16+x (10+1)/16x=5/(16+x) 11(16+x)=5*16x 176+11x=80x 176=69x x=176/69
5 1 5 --- + ----- = ----- + x 8x 16x 16 Multiply all terms by 16x, we get 10 + 1 = 5x + 16x^2 11 = 5x + 16x^2 16x^2 + 5x - 11 = 0 16x^2 + 16x - 11x -11 = 0 16x(x + 1) -11(x + 1) = 0 (16x - 11)(x + 1) = 0 This is possible if either (16x - 11) or (x + 1) is zero If 16x - 11 = 0 ==> 16x = 11 ==> x = 11/16 If x + 1 = 0 ==> x = -1 Therefore x = 11/16, -1
harikat so 176/69 is wrong
is x in the denom or not? (I've solved as it is)
u hv to confirm if I hv written the question correct at the beginning or angela... Who has written your question properly???
angela
Next time it would be better if u used some brackets :):)
ok thanks sorry.. a little rusty with this algebra
:)
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