Question

lim \[1+\sin \chi \over 1+\cos \chi\] where x approaches 0

Answer 1

1/2

Answer 2

yup

Answer 3

how?

Answer 4

sinx = 0 when x->0
cosx = 1 when x ->0

Answer 5

ِAs they said, just plug \(x=0\) into the given expression and you'll get \(\frac{1+\sin0}{1+\cos0}=\frac{1}{2}\).