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Mathematics 23 Online
OpenStudy (anonymous):

evaluate integral http://www.webassign.net/cgi-bin/symimage.cgi?expr=int_1%5E64%20%281%20%2B%202%20root3%28x%29%29%2Fsqrt%28x%29%20dx

OpenStudy (anonymous):

\[\sqrt{x}=x ^{1/2}\]Move denominator to numerator; multiply through.

OpenStudy (anonymous):

ok i am stuck on this: \[(1/2)/(1/2)+2^{5/6}/(5/6)\left(\begin{matrix}64 \\ 1\end{matrix}\right)\]

OpenStudy (anonymous):

\[= \int\limits_{1}^{64} ( x^{-\frac{1}{2} } + 2 ( x^{\frac{1}{3} - \frac{1}{2} } ) )\]

OpenStudy (anonymous):

\[= \int\limits_{1}^{64} ( x^{-\frac{1}{2}} + 2 x^{ -\frac{1}{6} } )dx \]

OpenStudy (anonymous):

so its not ^5/6?

OpenStudy (anonymous):

When you swing it to the top the 1/2 becomes negative.

OpenStudy (anonymous):

right

OpenStudy (anonymous):

so now what i do?

OpenStudy (anonymous):

wait i add one to each of the numorator?

OpenStudy (anonymous):

You start over. Integrate what elecengineer did. The negative is not showing on exponents.

OpenStudy (anonymous):

yes but then i have to add one which becomes: \[x^{1/2} /(1/2)+ 2^{5/6}/(5/6)\]

OpenStudy (anonymous):

You are writing rubbish. What is 2^(5/60?)

OpenStudy (anonymous):

so well can you show me please..so i can pick up where im going wrong

OpenStudy (anonymous):

\[\int\limits_{1}^{64}x ^{-1/2}+2x ^{-1/6}\]The negative not showing in exponent.

OpenStudy (anonymous):

ok so whats the next step

OpenStudy (anonymous):

Exponent work\[-(1/2)+(2/2)=(1/2)\]\[-(1/6)+(6/6)=(5/6)\]

OpenStudy (anonymous):

Got it?

OpenStudy (anonymous):

yes thats what i did

OpenStudy (anonymous):

next step please

OpenStudy (anonymous):

Well, you are confusing yourself. Above, you left of the x. Then instead of dividing, just flip it and multiply; makes everything cleaner.\[2x ^{1/2}+[2(6)/5]x ^{5/6}\]

OpenStudy (anonymous):

ok so you riciporcal the 5/6 to 6/5 and mulitiple by 2

OpenStudy (anonymous):

Yes, the 2 is already there as a coefficient.

OpenStudy (anonymous):

ok now i understand

OpenStudy (anonymous):

so now its 2x^(1/2)+(12/5)x^(5/6) right

OpenStudy (anonymous):

did you get this? it is a definite integral

OpenStudy (anonymous):

\[\int _1^{64} \frac{1}{\sqrt{x}}dx =2\sqrt{x}|_1^{64}=2(\sqrt{64}-\sqrt{1})=2\times 7=14\]

OpenStudy (anonymous):

im doin it differentlt like: {2(8) + (12/5) (2^5)}-(22/5)

OpenStudy (anonymous):

thats not right

OpenStudy (anonymous):

\[\int_1^{64} \frac{2}{\sqrt[6]{x}}dx = \frac{12}{5}\sqrt[6]{x^5}|_1^{64}\]

OpenStudy (anonymous):

\[=\frac{12}{5}(32-1)=74.4\]

OpenStudy (anonymous):

so "final answer" should be \[14+74.4=88.4\] unless i made an arithmetic mistake

OpenStudy (anonymous):

now can you explain why you are integrating and also converting decimals to fractions? what kind of math is this???

OpenStudy (anonymous):

this is calculus... and my textbooks shows me to do this

OpenStudy (anonymous):

oh ok. usually converting decimals to fractions comes first.

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