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find the sum of the finite geometric series by using the formular for Sn 1-1/3+1/9-1/27+1/81-1/243+1/729
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divide the sequence as follows... [1+1/9+1/81+1/729]-[1/3+1/27+1/243] thes r 2 diff gps .... solve for their sum as individuals nd subtrat it
to find the finite
yes there r three terms in each ... => n=3 r in each case is 1/9 a in case 1 is = 1 nd case 2 = 1/3 use theformula Sn = a[1-(r^n)]/(1-r)
I got it thank u soo much
no problem :)
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You could also use (1-r^n)/(1-r) with a ratio of -1/3 (a is 1) which will give u the same result.
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