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Evaluate the expression and write the result in the form a + bi. (5 + 3i)(2 − i) over/3 + i
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Solve it and Rationalise the Denominator ... :).
if i knew how to do that i wouldnt be asking lol
\[(5+3i)(2-i)=(10+3)+(6-5)i=13+i\]
so you have \[\frac{13+i}{3+i}=\frac{13+i}{3+i}\times \frac{3-i}{3-i}\]
the denominator is \[9+1=10\] and that is why you use this method
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the numerator is \[(13+i)(3-i)=40-10i\]
so you get \[\frac{40-10i}{10}=4-i\]
so is the final answer 4-i
o ok good
that is what i got, yes
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