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how do i find the x intercept of this function: x^4-12x^3+48x^2-64x
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is it y= all of that?
yes y= all of that
ok, not too hard, since the x-intercept will always happen when y=0, just set the lefthand side equal to 0 and solve for x
oh, not too hard huh, can you do
Well, it's 0 if x is 0.
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x=0 is one solution. FOr the remaining, solve: x^3-12x^2+48x-64 = 0
Testing by Rational Root theorem (after factoring x) gives possible roots of plus minus 1,2,4,8,16,32,64 That turns up 4. Now you've only got a quadratic to worry about.
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