Question

ok whats (csc (x))^2

Answer 1

1+cot^2(x)

Answer 2

how to integrate it?

Answer 3

Mine is a trig identity :P

Answer 4

very good malevolence

Answer 5

it is
\[\frac{1}{\sin^2(x)}\] for one

Answer 6

Haha, RECIPROCAL IDENTITY.

Answer 7

omg satellite is is smart

Answer 8

what do you to do with (cscx)^2

Answer 9

if you want an identity involving cosecant start with
\[\sin^2(x)+\cos^2(x)=1\] and then to get cosecant divide every term by sine

Answer 10

you get
\[\frac{sin^2(x)}{\sin^2(x)}+\frac{\cos^2(x)}{\sin^2(x)}=\frac{1}{\sin^2(x)}\]

Answer 11

giving
\[1+\cot^2(x)=\csc^2(x)\]

Answer 12

a more or less useful trick to know

Answer 13

hello my myininaya!

Answer 14

hey

Answer 15

so its 1/sin^2x?...

Answer 16

that is just the reciprocal identity yes.

Answer 17

will you tell me please what you want to do with (cscx)^2
because there is alot ways you can write that

Answer 18

not sure what you are after

Answer 19

almost time for coveted karnak award here.

Answer 20

ok here it is.... http://www.webassign.net/cgi-bin/symimage.cgi?expr=int%20%5C%28%20%28text%28csc%29%28t%29%29%5E2%20%20-%203%20e%2A%2At%5C%29%20dt

Answer 21

ok my myininaya would you like to do some algebra? check this out
http://openstudy.com/groups/mathematics?version=feed:get-live-help&referrer=mathematics&domain=tutorial.math.lamar.edu#/groups/mathematics/updates/4e1af3870b8bc2275747c0cb

Answer 22

\[\int\limits_{}^{}-\csc^2xdx=cotx+C\]
so what do you think the antiderivate of csc^2x is?

Answer 23

oh lorda mercy. this is ok!

Answer 24

look in the book and see what has derivative
\[csc^2(x)\]

Answer 25

i give you a hint: it is almost
\[\cot(x)\]

Answer 26

\[\frac{d}{dx}(-cotx)=\frac{d}{dx}(\frac{-cosx}{sinx})=\frac{-(-sinx)*sinx-cosx*(-cosx)}{\sin^2x}\]
\[=\frac{\sin^2x+\cos^2x}{\sin^2x}=\frac{1}{\sin^2x}=\csc^2x\]

Answer 27

so we have
\[\frac{d}{dx}(-cotx)=\csc^2x\]
what happens if we integrate both sides
\[\int\limits_{}^{}\frac{d}{dx}(-cotx)dx=\int\limits_{}^{}\csc^2x dx\]
\[-cotx+C=\int\limits_{}^{}\csc^2x dx\]

Answer 28

im sorry i was occupied by my baby boy...but yes i see -cot would be -cosx/sinx

Answer 29

ok so overall it would be 1/sinx^2 +3e^t^2?

Answer 30

? no