Question

(x^2-5x)/5x=x-1 is this correct?

Answer 1

no

Answer 2

no

Answer 3

also no

Answer 4

\[\frac{x^2-5x}{5x}=\frac{x(x-5)}{5x}=\frac{x-5}{5}\]

Answer 5

can cancel the x but not the 5 since 5 is not a factor of the first term.

Answer 6

oh yeah-thanks

Answer 7

In general it's not true but it is for x=0.

Answer 8

no its not

Answer 9

not in the form its in ,

Answer 10

Form is temporary. Changing the form doesn't change the solution set, as long as you're careful with zero divisors. Here it's exactly the same as x/5 - 1 = x - 1. Which has solution x=0.

Answer 11

dont worry :|

Answer 12

what on earth?

Answer 13

remember, they are different expressions

Answer 14

its like saying graph \[y=2x-2\] and graph \[\frac{y}{2x-2} =1\]

Answer 15

one has a hole at x=1

Answer 16

Interesting point. I guess the subtlety lies in the assumption that we never have divisors of zero, and I broke that assumption. I really should know better lol.