Question

Find all real solutions of the equation. (Enter your answers as a comma-separated list. If there is no real solution, enter NO REAL SOLUTION.)


(sqrt2x + 9)+ 3 = x

Answer 1

rewrite question please

Answer 2

Sqaure Root of 2x+9
+3=x

Answer 3

\[\sqrt{2x+9}\]

Answer 4

+3=x

Answer 5

thanks

NO SOLUTION

because it defines itself so its an infinity loop

Answer 6

the real solution is x = 1+sqrt(13)

Answer 7

what about this

Answer 8

think about the question at the very end you state the something is =x. Plug that expression into it self and you have a forever loop.

Answer 9

x = -3

Answer 10

no possible santistebanc because then the sqrt would have to be a negative

Answer 11

\(\sqrt{2x+9}+3=x\)..
Start by adding -3 to both sides and then square both sides \(\sqrt{2x+9}=x-3 \implies 2x+9=(x-3)^2 \implies 2x+9=x^2-6x+9\). Rearrange the terms after adding similar term you will get \(x^2-8x=0 \implies x(x-8)=0\). So, we have \(x=0\) or \(x=8\). If you check them by substituting in the original equation, you'll find that the only solution is \(x=8\).

Answer 12

what did you mean? sqrt(2 x+9+3) = x or sqrt(2 x+9)+3 = x
the first one is x = 1+sqrt(13) and the other is x = 8

both are real

Answer 13

now that im so confused

Answer 14

To be honest, you're the source of confusion because you didn't even write the question right. But, if the equation you want to solve is what I wrote in the first line of my comment, then you just have to follow the solution I gave.

Answer 15

yeah agree with AnwarA