x is not equal to -3; 6x to the second power minus 54 over 5x plus 15 help explain and solve i need to know how it's done

Question

anonymous · Answer

You cannot really solve this. All you can do is re-write it in a different form.

anonymous · Answer

$$6x^2-\frac{54}{5x}+15$$?

anonymous · Answer

$$6x^2 - 54 \over 5x + 15$$

Is my guess and you have to do it by long division.

anonymous · Answer

Sorry i meant simply

anonymous · Answer

it gives me an answer of 6x-3 over 5 but i am unsure how we got there

anonymous · Answer

which one of us has the correct 'starting problem' ?

anonymous · Answer

your do

anonymous · Answer

polpak

anonymous · Answer

Ok, so to simplify mine you must use long division.

anonymous · Answer

First lets get rid of a factor of 5.
5x + 15 = 5(x + 3)

So we will leave a factor of 5 on the bottom. and just divide by the other factor.
             6x   -18
          _____________
x  + 3 )  6x^2 + 0x - 54
           -6x^2 -18x
          ----------
                      -18x - 54
                      +18x +54
                     ----------
                                  0


So we have that
$${6x^2 - 54 \over 5x + 15} = \frac{1}{5}\cdot(6x-18) = \frac{6x-18}{5}$$