Question

divide: 9+2i/8-5i

Answer 1

Do the conjugate of the denominator. So: (9+2i)(8+5i)/(8-5i)(8+5i)

Answer 2

foil

Answer 3

Yes, and remember that \[i^2\] is -1

Answer 4

\[\frac{9+2i}{8-5i}*\frac{8+5i}{8+5i}\]\[\frac{72+45i+16i+10i^2}{64-25i^2}\]\[i^2=-1\]\[\frac{72+61i+(10*(-1))}{64-(25*(-1))}\]\[\frac{72+61i-10}{64+25}=\frac{61i-62}{89}\]