Question

find the x-intercept of the parabola with vertex (-3,-14) and y intercept (0,13) in (x1,y1) (x2,y2) form using - (y-k)=a(x-h)^2

Answer 1

vertex is (-3,-14) means you know it looks like
\[y=a(x+3)^2-14\]

Answer 2

and since you know that if x = 0, y = 13 replace x by 0 and set y = 13 to get a
\[13=a(0+3)^2-14\]
\[13=9a-14\]
\[27=9a\]
\[a=3\]

Answer 3

thus
\[y=3(x+3)^2-14\] or if you prefer
\[y+14=3(x+3)^2\]

Answer 4

so thats what i type? it saids in (x1,y1) (x2,y2) form ?

Answer 5

i have no idea what that means. it looks like you want
\[y+14=3(x+3)^2\]