find the x-intercept of the parabola with vertex (-3,-14) and y intercept (0,13) in (x1,y1) (x2,y2) form using - (y-k)=a(x-h)^2

Question

anonymous · Answer

vertex is (-3,-14) means you know it looks like 
$$y=a(x+3)^2-14$$

anonymous · Answer

and since you know that if x = 0, y = 13 replace x  by 0 and set y = 13 to get a
$$13=a(0+3)^2-14$$
$$13=9a-14$$
$$27=9a$$
$$a=3$$

anonymous · Answer

thus 
$$y=3(x+3)^2-14$$ or if you prefer 
$$y+14=3(x+3)^2$$

anonymous · Answer

so thats what i type? it saids in (x1,y1) (x2,y2) form ?

anonymous · Answer

i have no idea what that means.  it looks like you want 
$$y+14=3(x+3)^2$$