Question

find the x-intercepts of the parabola with vertex(6,27) and y-intercept (0,-81). write anwser in form (x1,y1)(x2,y2). if necessary ,round to the nearest hundredth . :D PLEASE HELP ME ! <3

Answer 1

ok

Answer 2

since the vertex is
\[(6,27)\] you know it looks like
\[y=a(x-6)^2+27\] so now you need a

Answer 3

if x = 0, you know y = -81 so replace x by 0 and set y = -81 to get
\[-81=a(0-6)^2+27\]
\[-81=36a+27\]
\[-108=36a\]
\[a=\frac{-108}{36}=-3\]

Answer 4

so your equation is
\[y=-3(x+6)^2+27\] or if you prefer
\[y-27=-3(x+6)^2\]

Answer 5

oh ok i understand thanks but love what is it in x1,y1 form x2,y2 form ?

Answer 6

since the parabola is shifted to the right, shouldn't the equation be -3(x-6)^2 + 27

Answer 7

the x intercepts are 3 and 9...

Answer 8

so you have to write them in as
\[(3,0)\] and \[(9,0)\]