Question

satellite73 please help me? attachment below, (only five questions)

Answer 1

someone help me please?

Answer 2

I only see question 2 and the choice is the second one

Answer 3

third one

Answer 4

for "helpme.2" it is the second choice

Answer 5

what about help me 4?

Answer 6

question 3 is the third choice

Answer 7

i need help me 4's answer

Answer 8

i need help with the attachment "helpme4"

Answer 9

451

Answer 10

i will say 451

Answer 11

oh and i am too late. sorry. mrjoselson got it

Answer 12

new one

Answer 13

25

Answer 14

oh and i am too late. sorry. mrjoselson got it

Answer 15

can someone help me pleazse ?

Answer 16

someone help me please ; sorry if im annoying you :(

Answer 17

@tabbey answer is
\[x^6-6x^3\]

Answer 18

thanks love :)

Answer 19

@scilaaax answer is to help1 is
\[g(12)=\sqrt{12-8}=\sqrt{4}=2\]
\[f(2)=-4\times 2+2=-6\]

Answer 20

so answer is -6. this means first do g, then do f

Answer 21

@tabbey
\[f(5)=2\]
\[f(2)=16\] so 16 is your answer

Answer 22

you two doing the same problems yes? what is this plato?

Answer 23

thanks love again <3 yuour the best :)

Answer 24

hello my myininaya! got lots of questions today from plato learning whatever that is

Answer 25

help!

Answer 26

what school?

Answer 27

i don't know how popular plato is but i know of one school who uses it

Answer 28

scilaax3

Answer 29

the 4th one tabby

Answer 30

\[g(24)=\sqrt{24+1}=\sqrt{25}=5\]
\[f(5)=-9\times 5+9=-40\]

Answer 31

f(g(x))=f(x^3)=9x^3+1

Answer 32

which ones for me ?

Answer 33

this is getting confusing

Answer 34

help2 answer is -40

Answer 35

thanks love :) another one on the way ^_^ teehee. sorry .

Answer 36

well i was talking to tabby

Answer 37

maybe we could start another thread yes? make it easier

Answer 38

sorry :( if this is getting confusing ;( we dont mean to & no we arent the same person ; we are in the same class thats it & thanks much love :)@myininaya

Answer 39

you guys are awesome :)

Answer 40

f(x)=h(g(x))
h(x)=x^3
g(x)=?
f(x)=(4x^2+11)^3
\[(4x^2+11)^3=(g(x))^3\]
so g(x)=4x^2+11

Answer 41

meaning ? what do u do just plug in ? or ... :/ <3

Answer 42

it looking for g(x) and g(x)=4x^2+11
so you plug in \[4x^2+11\]